Step 1: I was given the starting population of 1000
with a q² of .37, representing the frequency of
homozygous recessive genotype.
Step 2: Using the q² value (.37) I
square rooted it in order to find the q value, the frequency of the
recessive allele, which is .61
Step 3: Now that I have the q value,
I am now able to find the p value (the frequency of the dominant allele) by
subtracting .61 from 1 since the equation is p+q=1 getting .39 for p.
Step 4: With the p value I can find
p², the frequency of the homozygous dominant genotype, by squaring p (.39)
and from that I got .15
Step 5: Finally, I can find the
frequency of heterozygotes or 2pq by multiplying 2 x .61 x .39 and got the
value of .48
Step 6: Since we know the number of
individuals in the population, which is 1000, we can figure out the number of
individuals that hold each specific genotype ( homozygous dominant, heterozygous,
and homozygous recessive) by using q², p², and 2pq using the
equations below.
Homozygous Dominant
Individuals: 1000 x .15= 150 individuals
Heterozygous
Individuals: 1000 x .48= 480 individuals
Homozygous
Recessive Individuals: 1000 x .37= 370 individuals
